The sum of the digits in a two-digit number is 12. The digit in the tens place is 2 more than the digit in the ones place. The system of linear equations shown below represents this situation, where x is the digit in the tens place and y is the digit in the ones place. Solve the system to find the two-digit number. Lbrace x + y = 12 x − y = 2

The digit is 75

Step-by-step explanation:

x is the digit in the tens place

y is the digit in the ones place.

We are given a system of equations

x + y = 12 Equation 1

x - y = 2 Equation 2

Subtract Equation 2 from Equation 1

2y = 10

y = 10/2

y = 5

x - y = 2

x - 5 = 2

x = 2 + 5

x = 7

Since:

x is the digit in the tens place

x = 7 = 7 × 10 = 70

y is the digit in the ones place

y = 5 = 5 × 1 = 5

Hence, The digit is 75

0.84 dang lotta people are looking for this lol or if you round up its 1 but the overall answer to that is 0.84

step-by-step explanation: