A poster of area 6000 cm2 has blank margins of 10 cm wide on the top and bottom and 6 cm wide on the sides. Find the dimensions that maximize the printed area.

Step-by-step explanation:

A = Area of the poster =

x = Length of poster

y = Width of poster

Printed area would be

So we get the printable area as function

Differentiating with respect to x we get

Equating with zero

Printed area length would be and breadth would be

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²