A poster of area 6000 cm2 has blank margins of 10 cm wide on the top and bottom and 6 cm wide on the sides. Find the dimensions that maximize the printed area.

Step-by-step explanation:

A = Area of the poster =

x = Length of poster

y = Width of poster

Printed area would be

So we get the printable area as function

Differentiating with respect to x we get

Equating with zero

Printed area length would be and breadth would be

step-by-step explanation:

ok one would be money, and the other would be refreshments or something similar. if each bag of popcorn is 5.00 and each drink is half of that that means drinks are 2.50 the proper way to do that would to look and see how much of each you can buy without exceeding a limit of 30.00

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p