In a pet competition, it costs $42 to enter a cat and $31 to enter a dog. A total of 149 pets were entered and $5,026 was made. How many DOGS were entered in the competition?

Given :

In a pet competition, it costs $42 to enter a cat and $31 to enter a dog. A total of 149 pets were entered and $5,026 was made.

To Find :

How many dogs were their.

Solution :

Let, number of cats and dog are c and d.

c + d = 149   1)

42c + 31d = 5026   ...2)

Putting value of c in equation 2, we get :

42( 149 - d ) + 31d = 5026

6258 - 42d + 31d = 5026

11d = 6258 - 5026

11d = 1232

d = 112

Therefore, number of dogs in competition are 112.

Hence, this is the required solution.

arithmetic sequence: a sequnce in which the diffrence between any two consecutive terms is the same

step-by-step explanation:

2160ft3

step-by-step explanation: