The vertex of the graph of y = (x - 1)2 - 5 is

1,-5

Step-by-step explanation:

for y  = (x-h)^2 + k

the vertex is h,k

comparing

y=(x-1)^2-5  with  y  = (x-h)^2 + k

we have h = 1, k = -5

so the vertex of y=(x-1)^2-5  is  (1,-5)

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step-by-step explanation:

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