How do you solve the equation above using substitution? Please show work :)

the solution is (21/2, 19/2)

Step-by-step explanation:

The first equation, x = y + 1, has already been solved for x.  We can eliminate x in the second equatin by substituting y + 1 for x:

y = -(1/3)(y + 1) + 6

Let's eliminate fractions by multiplying all three terms by 3:

3y = y + 1 + 18

Combining like terms results in:

2y = 19, so that y = 19/2.

Substituting this 19/2 for y in the first equation, we get:

19/2 + 2/2 = x, or

x = 21/2

Thus the solution is (21/2, 19/2)

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