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Mathematics, 04.11.2020 01:00 ayoismeisalex

Let S be the set of all strings in a's and b's, and define C: S β†’ S by C(s) = as, for each s ∈ S. (C is called concatenation by a on the left.) Show that C is not onto.


Let S be the set of all strings in a's and b's, and define C: S β†’ S by C(s) = as, for each s ∈ S. (

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Let S be the set of all strings in a's and b's, and define C: S β†’ S by C(s) = as, for each s ∈ S. (C...
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