The second of three numbers is 11 less than the first. The third number is
5 less than the second. If the first
number is twice as large as the third,
find the three numbers.

The sum of three numbers is 112.

a+b+c=112

The second number is 5 times the first.

b=5a

so a+5a+c=112

6a+c=112

The third number is 20 less than the second. What is the second number?

c=5a-20

6a+5a-20=112

11a-20+20=112+20

11a/11=132/11

a=12

Step-by-step explanation:

6.5

step-by-step explanation:

you said it was in the question

~courtney

8(4)^8=72^feet to say that the total can conclude to 8(4) which as you know would mean 8 x 4. that equals 32w. 32^ could make a 72 answer as well. but your coefficent will remain w so your answer is 72w.

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