In △ACD, if AC ≅ AD, m∠A = (3x – 4)°, m∠C = (5x + 1)°, and m∠D = (7x – 27)°, find x and the measure of each angle. *

x = 14

A = 38

B = 71

C = 71

Step-by-step explanation:

Since we have a triangle, the addition of the measure of all the measure of the angles give 180

Thus;

3x-4 + 5x + 1 + 7x-27 = 180

15x-30 = 180

15x = 180 + 30

15x = 210

x = 210/15

x = 14

To get the measure of each of the angles, we substitute for x

A = 3x-4 = 3(14) - 4 = 38

B = 5x + 1 = 5(14) + 1 = 70 + 1 = 71

C = 7x - 27 = 7(14) - 27 = 98-27 = 71

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step-by-step explanation:

ez do it yourself lazy

x^3-4x^2+3x-2/x^2+1

step-by-step explanation:

factor the numerator and denominator and cancel the common factors