Triangle ABC has vertices A (1,1), B (3,2) and C (0,-2), It is dilated by a scale factor of 1/2 about the origin to create triangle A' B' C'. What is the length in units of side B'C'?

The length is 2.5 units

Step-by-step explanation:

Before we find the value of the length of the side, we need the measure of the coordinates after dilation

B’ = 1/2 B = 1/2(3,2) = (1.5, 1)

C’ = 1/2 C = 1/2( 0,-2) = (0,-1)

The measure of the length is the distance between the two points

Mathematically, that would be;

D = √(x2-x1)^2 + (y2-y1)^2

D = √(0-1.5)^2 + (-1-1)^2

D = √(2.25 + 4)

D = √6.25

D = 2.5 units

if a = 1,   and b = 2, then the answer is 47.99999999. if you round that to the nearest whole number, the answer is 48.

i use my brain for prombles like this maybe you could try it

step-by-step explanation: