"The distribution of grades in an introductory finance class is normally distributed, with an expected grade of 67. If the standard deviation of grades is 8, in what range would you expect 95.00 percent of the grades to fall? (Round answers to 2 decimal places, e. g. 15.25. Hint: Think in terms of what the expected highest and lowest scores would be for 95.00% of the students taking the exam.)"

The range of 95 percent of the grades will fall between 51.00 to 83.00

Step-by-step explanation:

Given;

mean of the distribution, = 67

standard deviation, = 8

The range in which 95 % of the grade will fall is given by;

Range = mean ± 2(standard deviation)

Range = 67 ± 2(8)

Range = (67 - 16) to (67 + 16)

Range = 51.00  to   83.00

Thus, the range of 95 percent of the grades will fall between 51.00 to 83.00

idk

step-by-step explanation: i just don't

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.