The mean height of women in a country (ages 20-29) is 64.5 inches. A random sample of 75 women in this age group is selected. What is the probability that the mean height for the sample is greater than 65 inches? Assume o=2.99.

0.07378

Step-by-step explanation:

We solve using z score formula

z = (x-μ)/σ/√n, where

x is the raw score = 65 inches

μ is the population mean= 64.5 inches

σ is the population standard deviation = 2.99

n = 75

z = 65 - 64.5 /2.99/√75

z = 0.5/0.345255461

z =1.4482

Probability value from Z-Table:

P(x<25) = 0.92622

P(x>25) = 1 - P(x<25)

= 1 - 92622

= 0.07378

The probability that the mean height for the sample is greater than 65 inches is 0.07378

i think the answer is .36

step-by-step explanation:

what i did was only 2.88 divided by 8

i dony know

step-by-step explanation: