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Mathematics, 03.11.2020 15:50 mvtthewisdead

What is the equation of the parabola shown below, given a focus at F(1, 5) and a directrix of x = βˆ’3? In addition, identify the vertex and the equation of the axis of symmetry for the parabola. x= \frac{1}{8}(y-5)^2-1 vertex: (βˆ’1, 5), axis of symmetry: y = 5 vertex: (5, βˆ’1), axis of symmetry: x = βˆ’3 vertex: (βˆ’2, βˆ’5), axis of symmetry: y = 2 vertex: (βˆ’1, 5), axis of symmetry: y = 5


x=\frac{1}{5}(y+5)^2 +2
x=\frac{1}{4} (y+2)^2-5
x=\frac-{1}{8} (y-5)^2-1
What is the equation of the parabola shown below, given a focus at F(1, 5) and a directrix of x = βˆ’

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What is the equation of the parabola shown below, given a focus at F(1, 5) and a directrix of x = βˆ’3...
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