What is the equation of a line that is perpendicular to the line y - 1 = -2 (x + 5) and that passes through the point (-3,2).

Step-by-step explanation:

Write the equation in the form of Y=mX+C so that it is easuer to find the gradientor slope

the slope is -2 .

since we need to find a perpendicular equation, the gradient or slope should be negative reciprocal of the gradient we have now which is -2

the perpendicular gradient = 1/2

coordinates: (-3,2)

y - 2 = (x + 3)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

y - 1 = - 2(x + 5) ← is in point- slope form

with slope m = - 2

Given a line with slope m then the slope of a line perpendicular to it is

= - = - =

and (a, b) = (- 3, 2), thus

y - 2 = (x - (- 3) ), that is

y - 2 = (x + 3) ← equation of perpendicular line

do you mean add both of the equations together

because if you do the answer is 10x-5

step-by-step explanation:

i need more info. are you looked to see there mph? how much they deliver? how far they go?

step-by-step explanation: