Solve the following: Find the side and perimeter of a square whose
diagonal is 7 cm.
(please write the full answer it is urgent i will mark as brainlist please write the full answer)

★ Given :-

★ To Find :-

★ Diagram :-

➳Let the side of the square be x cm.

➳Now, we know, each sides of square is of equal length.

➳Now, let the square be ABCD ( according to the attachment)

➳Therefore, AB = BC = CD = DA = x cm

➳The diagonal has divided the square into two triangles.

➳Now the each angles of a square is of 90°

➳Therefore, ∠DCB = 90°

➳And △DBC is a right angle triangle.

➳ Therefore, the side of the square = 4.95 cm

Now, the perimeter = 4 × side

➳ Therefore, the perimeter of the square is 19.8 cm^2

is this part of a question or something

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.