Write the equation in slope-intercep tform of the line that passes through(6, −11) and is parallel to the graph of y = −x2/3+ 12.

The equation in slope-intercept form of the line that passes through(6,−11) and is parallel to the graph of y = −x2/3+ 12. is

Step-by-step explanation:

We need to Write the equation in slope-intercept form of the line that passes through(6, −11) and is parallel to the graph of y = −x2/3+ 12.

The general equation of slope-intercept form is: y=mx+b

where m is slope and b is y-intercept.

Since both the lines are parallel so, they have same slope. (If 2 lines are parallel they have same slope)

So, slope for our equation will be -2/3 (Taken from the equation of line given y=-2/3x+12 and comparing it with general form y=mx+b the value of m is -2/3 )

Now, we need to find y-intercept using point (6,-11) and slope m= -2/3

We will use equation: y=mx+b

Putting values:

So, value of b is -7

Now, the equation of required line having slope  = -2/3 and b=-7 is:

The equation in slope-intercept form of the line that passes through(6,−11) and is parallel to the graph of y = −x2/3+ 12. is

7.25

step-by-step explanation:

we know that 7 equals to 7.0. we also know that 1/4=0.25. so we can add the two together and we get 7.25

none.

step-by-step explanation:

m

1

=

5

m1=5

b

=

−

1

b=-1

find the slope and y-intercept of the second equation.

tap for more

m

2

=

0

m2=0

b

=

−

6

b=-6

compare the slopes

m

m of the two equations.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

compare the two slopes in the decimal form. if the slopes are equal, then the lines are parallel. if the slopes are not equal, then the lines are not parallel.

m

1

=

5

,

m

2

=

0

m1=5,m2=0