Mathematics, 03.11.2020 07:10 23rwilliamson

Find the value of x. Round to the nearest tenth.

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Answer from: 21hendlill

Answer/Step-by-step explanation:

Apply trigonometric bratio formula where applicable, to find the value of x in each case. Recall the acronym, SOHCAHTOA. This will help toe ash determine which ratio formula to use depending on the information given.

4. $\theta = 33$

Opp = x

Hyp = 14

Therefore, apply SOH. Which is,

$sin(33) = \frac{x}{14}$

Multiply both sides by 14

sin(33)*14 = x

7.6 = x (nearest tenth)

5. $\theta = 29$

Adj = x

Hyp = 14

Therefore, apply CAH. Which is,

$cos(37) = \frac{x}{14}$

Multiply both sides by 14

cos(37)*14 = x

11.2 = x (nearest tenth)

6. $\theta = 29$

Opp = x

Adj = 5.4

Therefore, apply TOA. Which is,

$tan(29) = \frac{x}{5.4}$

Multiply both sides by 5.4

tan(29)*5.4 = x

3.0 = x (nearest tenth)

7. $\theta = 55$

Opp = x

Adj = 33

Therefore, apply TOA. Which is,

$tan(55) = \frac{x}{33}$

Multiply both sides by 33

tan(55)*33 = x

47.1 = x (nearest tenth)

Answer from: Quest

step-by-step explanation:

it have 5 sides and 5 identicle angle.the rest does not have the same property as b.

brainliest

Answer from: Quest

tell you what. i'll find the length of the medians and you can fill in the blanks where they belong.

b = (2a,0)

r = (a/2,b/2) remember these things are medians. they go to the 1/2 way point of the line opposite the vertex they face.

br^2 = (2a - a/2)^2 + (0 - b/2)^2

br^2 = (3/2 a) ^2 + b^2 / 4

br^2 = 9/4 a^2 + b^2 / 4 we need to find some relationship between a and b.

let's try ab = bc

ab = 2a

bc = (2a - a)^2 + (b - 0)^2

bc = sqrt(a^2 + b^2)

ab = bc

2a = sqrt(a^2 + b^2) square both sides.

4a^2 = a^2 + b^2 subtract a^2 from both sides.

sqrt(3a^2) = sqrt(b^2)

sqrt(3)a = b

let's put b into br^2

br^2 = 9/4 a^2 + 3b^2 / 4

br^2 = 12 a^2 / 4

br^2 = 3a^2

br = sqrt(3) * a

c = (a,b) ; p = (a,0) this is another application of the distance formula, and it is a good one.

cp^2 = (a - a)^2 + (b - 0)^2

cp^2 = 0 + b^2

cp^2 = b^2 which you can see from the diagram.

cp = sqrt(b^2)

cp = b but b = sqrt(3) * a

cp = sqrt(3)*a

a = (0,0)

q = (3/2) a, b/2

aq^2 = (3a/2 -0)^2 + (b/2 - 0)^2

aq^2 = 9a^2/4 + b^2/4

but b = sqrt(3) * a

aq^2 = 9a^2 / 4 + (sqrt(3)*a)^2 /4

aq^2 = 9 a^2/ 4 + 3 a^2 / 4

aq^2 = 12 a^2/4

aq^2 = 3 a^2

aq = (sqrt 3) * a which agrees with the other two.

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Find the value of x. Round to the nearest tenth.
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