Mark you Brainliest If x1, x2, x3, ..., x8 are the roots of the eighth-degree polynomial, 2x^8+bx^7+cx^6+dx^5+ex^4+fx^3+gx^2+ hx+m,

find the value of b when:

x1 + x2 + x3 = 6

x2 + x3 + x4 = 18

x3 + x4 + x5 = 9

x4 + x5 + x6 = −3

x5 + x6 + x7 = −9

x6 + x7 + x8 = −6

x7 + x8 + x1 = −2

x8 + x1 + x2 = 2

2(2x + 3) = -4 + 2(2x + 5)

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 6

4x - 6 + 6 = 4x - 6 + 6

4x = 4x

x = x

unlimited solutions.

an = 22 + (n-1) *6

110 seats

step-by-step explanation:

an=a1+(n-1)(d)

a1 = 22   this is the first item in the sequence

d =6   this is how the sequence goes up

a)   an = 22 + (n-1) *6

b) a12 = 22 + (12-1) *6

    a12 = 22+11*6

  a12 = 22 +88

  a12 = 110