The graph of line BC is shown. Create an equation for a line perpendicular to line BC that passes through point A.

y = 3x + 1

Step-by-step explanation:

Coordinates of the points given on line BC,

A(0, 1), B(-3, 2) and C(3, 0)

Since, slope of a line passing through two points and is,

m =

Therefore, slope of line BC,

Let the slope of a line perpendicular to BC =

By the property of perpendicular lines,

Since, equation of a line passing through point and slope m is given by,

Therefore, equation of a line passing through A(0, 1) and slope = 3,

y - 1 = 3(x -0)

y - 1 = 3x

y = 3x + 1

Equation of the perpendicular line on BC and passing through point A is,

y = 3x + 1

ddsf

step-by-step explanation:

dfs