Lines AD and BC are parallel. A

D

150

45°

B

F

Find the measures of the three angles in triangle in ADE.

Angle ADE -

degrees

Angle DAE =

degrees

Angle DEA

_degrees

T

*see attachment for the missing figure

Angle ADE = 45°

Angle DAE = 30°

Angle DEA = 105°

Step-by-step explanation:

Since lines AD and BC are parallel, therefore:

Given that angle Angle CBE = 45°,

Angle ADE = Angle CBE (alternate interior angles are congruent)

Angle ADE = 45° (Substitution)

Angle DAE = Angle ACB (Alternate Interior Angles are congruent)

Angle ACB = 180 - 150 (angles on a straight line theorem)

Angle ACB = 30°

Since angle DAE = angle ACB, therefore:

Angle DAE = 30°

Angle DEA = 180 - (angle ADE + angle DAE) (Sum of angles in a triangle)

Angle DEA = 180 - (45 + 30) (Substitution)

Angle DEA = 180 - 75

Angle DEA = 105°

(0.2)+(-8)=0.3+-3+0.3m is the equation i guess? ?

step-by-step explanation:

the height of the surface increases from the center out to the sides of the road.

step-by-step explanation:

as we move out we move away from the x-axis.

and as mentioned in the problem statement that height of a road increases when we move away from the center x.

hence proved that 3rd option

the height of the surface increases from the center out to the sides of the road.

is the correct option.