The rate of change in revenue for Under Armour from 2004 through 2009 can be modeled by dR dt = 13.897t + 284.653 t where R is the revenue (in millions of dollars) and t is the time (in years), with t = 4 corresponding to 2004. In 2008, the revenue for Under Armour was $725.2 million.† (a) Find a model for the revenue of Under Armour. (Round your constant term to two decimal places.) R(t) = Correct: Your answer is correct. (b) Find Under Armour's revenue in 2007. (Round your answer to two decimal places.)

a

  The model is

b

  The revenue for 2007 is  

Step-by-step explanation:

From the question  we are told that

  The rate of change in revenue is  

   The revenue at 2008 is  

Generally we are told from the question that the revenue is denoted as R so to obtain R we integrate the both sides of rate of change in revenue, so  

=>  

From the question at  t = 8 ,  

So

=>

=>

So

At t = 7 the  Under Armour's revenue is mathematically represented as

=>  

=>  

step-by-step explanation:

d

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2