Problem # 2: Work problem Gerald can travel 40 miles on his motorbike at the same time, it takes Fitz to travel 15 miles on his bicycle. If Fitz rides his bike 20 mi/h slower than Gerald rides his motorbike, find each rate. Step 1: (R) – Let x be the rate of motorbike in mi/hr. Then, represent the rate of bicycle in mi/hr Remember: distance = rate x time Time for the motorbike = 40/x, Time for the bicycle = 15/ (x – 20) time for motorbike = time for bicycle Step 2: (D) 40= Step 3: (A) 40 (x – 20) = 40x – 800 = 15x40x – 25 x = 800 25x = 800 x = Substituting the value of x. − 20 = 32- 20 = 12 So, the rate of the motorbike is mi/h and the rate of the bicycle is mi/h. Step 4: (V) (2 Points ) Fill in the blank in step 1 to 3, for step 4 show the complete solution *