A boy has 11 coins in dimes and quarters. Their value is $1.70. How many of each does he have? Which of the following equations could be used to solve the problem? a. 0.10x + 0.25(11 - x) = 1.70 b. 25x + 10(11 - x) = 1.70 c. x + (11 - x) = 1.70

6 quarters 2 dimes

Step-by-step explanation:

so if you count a quarter as 25 cents it would go

25 50 75 $1 $1.25 $1.50 and you can not do another one that would make it be $1.75 so

$1.50 + 20 cents would be $1.70

i hope this helps :)

21 i watched a 3 hr vid explaining it

step-by-step explanation:

du what else would it be

brainliest

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation: