Five years ago, Charlie was twice older than Priya. What are their ages now if in 3 years the sum of their ages will be 76? I need both ages thx

present age of charlie is  45 years

present age of priya is  25 years

Step-by-step explanation:

Let start from five years ago

Let at that age of Priya was x years

given that

Charlie was twice older than Priya

age of Charlie = 2x

present age of charlie = age 5 years ago + 5 years = 2x + 5

present age of priya = age of priya  5 years ago + 5 years x + 5 = x + 5

age of charlie 3 years from now = present age of charlie + 3 years

age of charlie 3 years from now =2x + 5 + 3 = 2x + 8

age of priya 3 years from now = present age of priya + 3 years

age of priya 3 years from now =x + 5 + 3 = x + 8

Given that

in 3 years the sum of their ages will be 76

thus

sum of their ages in 3 years from now = x + 8 + 2x + 8 = 76

=> 3x + 16 = 76

=> 3x = 76-16 = 60

=> x = 60/3 = 20

Thus,

present age of charlie =  2x + 5 = 2*20 + 5 = 45 years

present age of priya = x + 5 = 20 + 5 = 25 years

-4

step-by-step explanation:

do 6-10=

if u need it to be negative.

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

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