Unit 1 Geometry basics Homework 5 Angle Relationships. Number 9

Here is their argument. given the obtuse angle x, we make a quadrilateral abcd with ∠dab = x, and ∠abc = 90◦, and ad = bc. say the perpendicular bisector to dc meets the perpendicular bisector to ab at p. then pa = pb and pc = pd. so the triangles pad and pbc have equal sides and are congruent. thus ∠pad = ∠pbc. but pab is isosceles, hence ∠pab = ∠pba. subtracting, gives x = ∠pad−∠pab = ∠pbc −∠pba = 90◦. this is a preposterous conclusion – just where is the mistake in the "proof" and why does the argument break down there?

On a coordinate grid, point p is at (4, 3) and point r is at (−2, −5). points q and s are a reflection of both points across the x-axis. what are the coordinates of q and s? q(−4, 3), s(2, −5) q(4, −3), s(−2, 5) q(−4, −3), s(2, 5) q(−4, 3), s(−2, 5) ; -; i can't figure it out, if someone can me with the answer,that would be nice

What is this inequality notation? t is less then or equal to 2