Please help me with this equation. It’s solving systems of equations.

Moving downstream (with the current), the boat moves at a rate of (252 mi)/(12 h) = 21 mph. Upstream (against the current), it moves at a rate of (252 mi)/(84 h) = 3 mph.

When traveling downstream, the boat's speed is the sum of its own speed in still water and the speed of the current. It's the same going upstream, but the boat and current move in opposite directions. Let b and c denote these speeds, respectively. Then

downstream: b + c = 21 mph

upstream:      b - c = 3 mph

Adding these equations eliminates c and lets us solve for b :

(b + c) + (b - c) = 21 mph + 3 mph

2b = 24 mph

b = 12 mph

Now solve for c :

12 mph + c = 21 mph

c = 9 mph

only 10/60 isn't equivalent

hope this : )

its a trick question

step-by-step explanation:

dogs love water, just turn on the hose and it will run in circles chasing the water all day : )