-2(y-5) + 10 = 6y + 20 how many solutions does the equation have? one solution, No solution, infinite solutions or cannot determine? help me out please

No solution

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

−2(y−5)+10=6y+20

(−2)(y)+(−2)(−5)+10=6y+20(Distribute)

−2y+10+10=6y+20

(−2y)+(10+10)=6y+20(Combine Like Terms)

−2y+20=6y+20

−2y+20=6y+20

Step 2: Subtract 6y from both sides.

−2y+20−6y=6y+20−6y

−8y+20=20

Step 3: Subtract 20 from both sides.

−8y+20−20=20−20

−8y=0

Step 4: Divide both sides by -8.

−8y

−8

=

0

−8

y=0

< 4, -5>

step-by-step explanation:

starting from g. we move 4 right and then 5 down to get to h. that means the vector is < 4, -5>

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.