What is the value of x, rounded to one decimal place?

x ≈ 5.9

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

x² + 2.7² = 6.5²

x² + 7.29 = 42.25 ( subtract 7.29 from both sides )

x² = 34.96 ( take the square root of both sides )

x = ≈ 5.9 ( to 1 dec. place )