lin's dad bought a tablet. he pays the same amount each month for a subscription to a movie streaming service. the graph represents how much money he spent, y, for the tablet and x months of the service. Which graph corresponds to this situation?

In this exercise, we have to recognize the best graph that corresponds to what is treated in the text, that is, the graph that best corresponds to a monthly fee, in this way we find that it is:

Graph 1

First, we are dealing with finances in this way, we have that a tablet has already been purchased so our chart will not start at the null point (x=0) but from the value of the purchased item. In this way, we know that graphics 4, 5 and 6 must be excluded.

In addition to the purchased item, we know that the monthly fee is the same amount every month as long as this program exists  so the movement from a point in the x axis to represent a month, should tally with a movement in the y axis that will be equal each time. This rules out graphs 2 and 3 as the movements on Y are not equal on the line.

This leaves graph 1 which means that Lin's dad paid $10 for the tablet and then pays $5 every month for a subscription to a movie streaming website.

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Graph 1

Step-by-step explanation:

At 0 months, Lin's dad had already spent money to buy the tablet so the line should not start at 0. That rules Graphs 4, 5 and 6 out.

He pays the same amount every month so the movement from a point in the x axis to represent a month, should tally with a movement in the y axis that will be equal each time. This rules out Graphs 2 and 3 as the movements on Y are not equal on the line.

This leaves Graph 1 which means that Lin's dad paid $10 for the tablet and then pays $5 every month for a subscription to a movie streaming website.

93.8

step-by-step explanation:

lets say, first number = x

second number = 3x+7

total = 49

(x)+(3x+7)= 49

4x+7 = 49

4x = 42

x = 42/4

x= 10.5

x= 10.5

3x+7 = 3(10.5)+7 = 93.8

hope this

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.