A truck can be rented from Company A for $130 a day plus $0.30 per mile. Company B charges $40 a day plus $0.60 per mile to rent the same truck. Find the number of miles in a day at which the rental costs for Company A and Company B are the same.

300 miles

Step-by-step explanation:

Let x= Number of miles driven by both cars.

As per given,

For Company A

Charges = $130 a day plus $0.30 per mile.

i.e. Total charge = 130+0.30x

For Company B

Charges =$40 a day plus $0.60 per mile

i.e. Total charge =40+0.60x

When the rental cost for both company is same,

40+0.60x=130+0.30x

⇒ 0.60x-0.30x= 130-40

⇒ 0.30x= 90

⇒ x= 90÷0.30

⇒ x=  300

hence,  the number of miles in a day at which the rental costs for Company A and Company B are the same = 300

every 5 customers that walk in, only 2 buy popcorn.

step-by-step explanation:

basically 2/5.

brainliest would be appreciated.

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )