Your neighbor Philip buys a new alarm system that has two alarms (main and backup) with a 0.01 probability of a system failure. After reading the manual, he discovers that the second alarm has a 0.05 probability of failing. What is the probability of the first alarm failing?

0.2

Step-by-step explanation:

Let P(A) = probability of first alarm failing and P(B) = probability of second alarm failing = 0.05. Since the events are independent, we have that the probability of both alarms failing or of system failure is P(A ∪ B) = P(A) × P(B).

Since the probability of both alarms failing or of system failure, P(A ∪ B) = 0.01, then the probability of the first alarm failing P(A) = P(A ∪ B)/P(B) = 0.01/0.05 = 0.2.

So, the probability of the first alarm failing P(A) = 0.2

the cat is blue because the probability of extension towards the prefix of the diameter of the circle could only mathematically equal to the sum of the roots of the carrots from   your garden.

step-by-step explanation: