A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find out the time at which the rocket will reach its max, to the nearest 100th of a second. y=-16x^2+263x+92

8.39 seconds

Step-by-step explanation:

Given the equation which models the height of a rocket:

y=-16x^2+263x+92

Time taken to reach maximum height ; = total total time of flight / 2

Total time of flight is obtained at h = 0

Hence +,

y=-16x^2+263x+92 ; y = 0

-16x^2+263x+92 = 0

Using the Quadratic equation solver :

X = 16.78 or x = -0.3466

Time can't be negative

Hence, total time of flight= 16.78

Therefore, time taken to reach maximum height :

Total time of flight / 2

= 16.78 / 2

= 8.39 seconds

5.5

step-by-step explanation:

the 3rd on is correct

step-by-step explanation: