Katherine is checking the prices of two different catering companies for her wedding reception. Brenda's Bridal Catering charges $300 for a cake plus $18 per person. Sarah's Complete Catering charges $450 for a cake plus $15 per person. Katherine really likes the cake from Sarah's Complete Catering, so she wants to use that company for her reception. Which inequality can be used to find x, the maximum number of people she can invite to the reception so that the total charge from Sarah's Complete Catering is less than the total charge at Brenda's Bridal Catering?

Maximum of 50 persons

Step-by-step explanation:

Straight line equation

let the total prices be y

and the number of persons be x

1.  Brenda's Bridal Catering charges

the expression for the charges is

y=mx+c

y=18x+3001

2.  Sarah's Complete Catering charges

the expression for the charges is

y=mx+c

y=15x+4502

equating 1 and 2 we can then solve for the number of guest as

18x+300=15x+450

18x-15x=450-300

3x=150

divide both sides by 3

x=150/3

x=50

x<=50

Therefore she can invite a maximum of 50 persons

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer

i dont know men

step-by-step explanation: