Complete the equation for the horizontal line that passes through (11, 4).
Y=

We have that from the co-ordinates given that

From the Question we are told that

Horizontal line that passes through (11, 4).

The co-ordinates represents the x and y

Generally the equation for the line  is mathematically given as

Therefore

The equation of the

From the co-ordinates given

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y = 4

Step-by-step explanation:

A horizontal line parallel to the x- axis has equation

y = c

where c is the value of the y- coordinates the line passes through.

The line passes through (11, 4) with y- coordinate 4 , thus

y = 4 ← equation of horizontal line

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

4x and 6y

im not sure though