This problem Involves empirical probability. The table shows the breakdown of 87 thousand Single parents on active duty In the U S. military In a certain year. All numbers are In thousands and rounded to the nearest thousand. Use the data In the table to find the probability that a randomly selected single parent in the U S. military IS In the Army. Army Navy Marine Corps Air force Total
Male 27 22 4 11 64
Female 11 7 1 4 23
Total 38 29 5 15 87

The probability that a randomly selected single parent in the U S military is In the Army is:

A certain lottery consists of selecting five different numbered balls from numbered 1 to 16 white balls and one from 1 to 12 gold Mega balls. A player wins the jackpot by matching all five numbers drawn from white balls (1 through 16) and matching the number on the gold Mega Ball (1 through 12). What is the probability of winning the jackpot?

The probability of winning the Jackpot is:

1.) 38/87

2.) 1 / 56784

Step-by-step explanation:

Given the data :

Army_Navy_ MarineCorps_ Air force_ Tot

Male__ 27___ 22 411 64

Female 11 7 1 4 23

Total _ 38___ 29 5 15 87

The probability that a randomly selected single parent in the U S military is In the Army is:

P = number of required outcome/ Total possible outcomes

P(single parent) :

Number of required outcomes = (number of single parents in the army = 38000

Total number of single parents in the military = 87000

P(single parent in army) = 38000 / 87000 = 38/87

B) To Win Jackpot:

16C5

Using the combination formula:

n! / (n-r)!r!

Using calculator :

16C5 = 4368

Winning number set = 1

Probability of winning number set = 1 / 4368

Probability of picking a correct (1) gold mega ball

Number of gold mega balls = 13

= 1/13

1/4368 * 1/ 13 = 1 / 56784

there are 25 people coming to the party

step-by-step explanation:

the text says that there will be 22 children at this party, 1 teacher, and 2 parents. so if you add them all together (22+1+2) it will equal 25. (=25)