Suppose that a sample of n students at the same university (instead of n) determines that % of the sample use the web browser. At the level of significance, is there evidence that the market share for the web browser at the university is greater than the worldwide market share of %?

Complete Question

The worldwide market share for a web browser was 20.5% in a recent month. Suppose that a sample of 200 random students at a certain university finds that 50 use the browser.

At the 0.05 level of significance, is there evidence that the market share for the web browser at the university is greater than the worldwide market share of 20.5%?

The decision rule is

Fail to reject the null hypothesis

The conclusion is

There is no sufficient evidence to show that the market share for the web browser at the university is greater than the worldwide market share of  20.5 %?

Step-by-step explanation:

From the question we are told that

          The population proportion is  

          The sample size is  n  =  200

          The number that uses the browser is  k =  50

          The level of significance is  

Generally the sample proportion is mathematically represented as

=>    

The null hypothesis is  

The  alternative hypothesis  is  

Generally the test statistics is mathematically represented as

=>      

=>      

Generally the area under    to the right is  

From the value we obtained we can see that the hence

 The decision rule is

Fail to reject the null hypothesis

   The conclusion is

There is no sufficient evidence to show that the market share for the web browser at the university is greater than the worldwide market share of 20.5 %?

it is a. 4.2 because 7.6-3.4 gets the remaining length of 4.2. i might be wrong but i am pretty sure this is the answer.

answer: 0.64

step-by-step explanation: