Write a polynomial fx that satisfies the given conditions. Express the polynomial with the lowest possible leading positive integer coefficient. Polynomial of lowest degree with lowest possible integer coefficients, and with zeros 5-32i and 0 (multiplicity 4).

f(x)=

Step-by-step explanation:

Find the question attached.

Given the zero of the polynomial 5+3i and 0, this means that (x-0) and (x-(5+3i)) are factors

Multiplying the factors together we have;

= x((x-(5+3i))

= x(x-5-3i)

= x²-5x-3xi

Hence the polynomial expression of the zeros is x²-5x-3xi

you probably already have the answer but anyways it's b. 15.0

step-by-step explanation:

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180