Find the smallest of the fractions 1/6 11/12 5/6 and 10/12 using a benchmark 0 to 1 which fraction is closest to 0

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube

236 cm 16 time 12 = 192

6 times 7 = 42

192+42

i would think "anyone would want the best for their child" is correct