Shares in stock of a new company are selling for $3.75 per share. An investor has $800. Which inequality can be solved to show the number of shares s he can buy?

Given:

Price of each share = $3.75

Total amount invertor has = $800

To find:

The inequality that can be solved to show the number of shares s he can buy.

Solution:

Let x be the number of shares he can buy.

Price of 1 share = $3.75

Price of x shares = $3.75x

An investor has $800.

The price of x shares must be less than or equal to the amount he has. So,

Divide both sides by 3.75.

So, the maximum possible integer value of x is 213.

Therefore, the equation inequality is and he can buy 213 shares.

answer: domain and range mean all possible values of x and y that could be substituted to the inequality. a solution means all possible values that make the inequality statement true. so while the range is still all real numbers, the solution is the shaded area, for which y will always be greater than the line of the function.

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b