A survey of 136 American adults measured each participants weight in pounds. If their individual weights were placed in order from smallest to largest give the position (location) of the median. If the median is located between two values give the location of the two middle values

the location of the two middle values are ; (68th and 69th) terms

Median  = (68th + 69th) / 2

Step-by-step explanation:

Median can be simply referred to as the middle value if the sample number size (n) is an odd number or average of the two middle values in a given data set if the sample number size (n) is an even number

the given data set has to be arranged from the smallest number to the biggest number before taking the middle number as median or taking the average of the two middle number as median if the sample number size (n) is an even number.

Here our n = 136 which is an even  number

So,

Median = Average of the two middle numbers

= [ (n / 2)th term + ((n/2) + 1)th term ] /2

= [ (136/2)th term + ((136/2) + 1 )th term ] /2

Median  = (68th + 69th) / 2

therefore the location of the two middle values are ; (68th and 69th) terms

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?