A coin is tossed and a six​-sided die numbered 1 through 6 is rolled. Find the probability of tossing a head and then rolling a number greater than 5.

Step-by-step explanation:

This type of probability is independent i.e the occurrence of one does not affect the other.

Probability = expected outcome/total outcome

For a coin:

The total sample space = {H, T} i.e 2

The probability of tossing a head will be:

P(a head) = 1/2

For a die:

Sample space S = {1, 2, 3, 4, 5, 6}

Total number of sample space n(S) = 6

If a number greater than 5 is rolled, the event outcome will be E = {6}

Pr(S>5) = n(E)/n(S)

Pr(S>5) = 1/6

The probability of tossing a head and then rolling a number greater than 5 is expressed as:

Pr(H and S>5) = Pr(H) * Pr(S>5)

Pr(H and S>5) = 1/2* 1/6

Pr(H and S>5) = 1/12

Hence the probability of tossing a head and then rolling a number greater than 5 is 1/12

she played for 18.75 hours.

step-by-step explanation:

if she played 2/4 of a hour on tuesday. and there is 60 minutes in an hour and 60 divided by 4 is 7.5. and she played 2/4 of an hour on thursday then again 60 divided by 4 is 7.5, you add 7.5+7.5=56.25. now you have to do 1/4 of an hour, it equals 3.75. now you have to add them all up. 3.75+7.5+7.5=18.75

i hope this and i hope you get it right. it took me a while to get this done for you. : )