Mathematics, 28.10.2020 14:00 pr4ever

En un elevador de estación de servicio en el embola grande mide 30cm de diámetro y el pequeño 2 cm de diámetro ¿ que fuerza se necesitará ejercer en el embola pequeño para levantar un automóvil que justo con el embola grande y las vigas de soporte pesa 35,000N?

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Answer from: cuddleslugsovifat

Necesitamos una fuerza de 155.556 newtons para el émbolo pequeño.

Step-by-step explanation:

Podemos resolver este problema a través del Principio de Pascal, el cual establece que la presión se transmite por igual a través de un sistema cerrado, el cual está representado por el fluido hidráulico del elevador. Asimismo, quiere decir que la presión hidrostática sobre el émbolo pequeño y la presión sobre el émbolo grande son iguales. Entonces:

$p_{1} = p_{2}$ (Eq. 1)

Donde:

$p_{1}$ - Presión sobre el émbolo grande, medido en pascales.

$p_{2}$ - Presión sobre el émbolo pequeño, medido en pascales.

Por la definición de presión tenemos que la fuerza aplicada sobre el émbolo pequeño ( $F_{2}$ ), medida en newtons:

$\frac{F_{1}}{\frac{\pi}{4}\cdot D_{1}^{2}} = \frac{F_{2}}{\frac{\pi}{4}\cdot D_{2}^{2}}$

$F_{2} = \left(\frac{D_{2}}{D_{1}} \right)^{2}\cdot F_{1}$ (Eq. 2)

Donde:

$F_{1}$ - Fuerza aplicada sobre el émbolo grande, medida en newtons.

$D_{1}$ , $D_{2}$ - Diámetros de los émbolos grande y pequeño, medidos en metros.

Si sabemos que $F_{1} = 35000\,N$ , $D_{1} = 0.30\,m$ y $D_{2} = 0.02\,m$ , entonces la fuerza necesaria para el émbolo pequeño es:

$F_{2} =\left(\frac{0.02\,m}{0.30\,m} \right)^{2}\cdot (35000\,N)$

$F_{2} = 155.556\,N$

Necesitamos una fuerza de 155.556 newtons para el émbolo pequeño.

Answer from: Quest

step-by-step explanation:

Multiple choice: select the best answer and click "submit." what is the name of the sides of the t

Answer from: Quest

the population of other specie of birds will decline or other specie of birds will find some alternate source of food to survive.

explanation:

according to the competitive exclusion principle, which is also known as gause's law, two specie living in the same niche and feeding on the same resource cannot co-exist stably.

as we have well studied the theory of natural selection which states that only those organisms survive which have better tendency to compete for food and adapt to the environmental conditions.

coming towards the question, what wi ll happen when one species outcompetes the other for the small fish , the other specie will not get enough food and will start to die or decline in population. eventually either other specie needs to find another alternative food source for itself or migrate at some other location where there is less competition otherwise it will just not exist anymore at that niche.

hope it !

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