The trinomial x2 bx c factors to (x m)(x n). if b is negative and c is positive, what must be true about m and n?

For c to be positive, and for b to be negative, m must be negative and n must be negative.

X^2 - bx + c = (x - m)(x - n).

c is the product of m and n. If both m and n are positive, c would be positive. However b is the sum of m and n, therefore to make b negative, both m and n must be negative to ensure that the product of m and n is positive

Both m and n should be negative

Step-by-step explanation:

Comparing this with

, we get,

b = m + n and c = mn

We have been given that c should be positive. So, we have two cases:

1. Both m and n should be positive and

2. Both m and n should be negative

Case 1: Both m and n are positive

If both m and n are positive, then so is mn = c.

But, note that m + n (= b) will also be positive. But, it is given that b should be negative. So, this case is not possible.

Case 2: Both m and n are negative

If both m and n are negative, then mn (= c) is positive.

Also, m + n (= b) is negative.

Hence, this is the correct case.

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40

answer:   x*94 +688*6   = 267*100

94x+4128=26700    

94x=22572     /94

x=240.128

step-by-step explanation: mark as brainlest reallly need it thx