Due Today!!
Line v passes through point (6, 6)
and is perpendicular to the graph 9
y β 1...
Mathematics, 28.10.2020 02:00 bryanna0105
Due Today!!
Line v passes through point (6, 6)
and is perpendicular to the graph 9
y β 1 = 4(x + 8) y = β4x + 15 16x + 4y = 9 y = β4x of y = _3_x β 11. Line w is parallel 4 to line v and passes through point (β6, 10). What is the equation in slope-intercept form of line w?
Answers: 3
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