IF YOU CAN GET THIS YOU CAN GET SOME POINTS HURR BRAINLIEST IS WAITING My twin lives at the reverse of my house number. The difference between our house numbers ends in two. What are the lowest possible numbers of our house? MY HOUSE NUBER IS 19

Suppose, the number of one of the houses is “xy”, whose numerical value = (10x + y).

So, the number of the other house is “yx”, whose numerical value = (10y + x).

Let, “xy” > “yx”.

Now, difference of house numbers = {(10x + y) - (10y + x)} = {9 * (x - y)}; so the difference is a multiple of 9.

Now, the smallest positive number, divisible by 9, that ends with 2 is 72 = (9 * 8).

So, (x - y) = 8.

Since, 0 ≤ x, y ≤ 9; so, there are two solutions in hand:

I) x = 8, y = 0……………………..this makes the house numbers: “80” and “08”.

II) x = 9, y = 1…………………..this makes the house numbers: “91” and “19”.

So, the lowest possible numbers of the houses are “80” and “8” (not “91” and “19”).

A single digit number can not have its reverse number. hence 10,20,30,40,50,60,70,80 and 90 can not be the house number

Reverse of these numbers is same, hence 11,22,33,44,55,66,77,88 and 99 can not be the house number

For other reverse numbers the difference will be in multiples of 9 like 9,18,27,36,45,54,63,72,81

As the difference between house numbers ends in two, the lowest possible numbers of our house are 19 and 91

When 0 (zero) also considred as part of house number, the lowest possible numbers of our house are 08 and 80

im trinna find out'

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