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Mathematics, 27.10.2020 20:40 Riohxncho
PLEASE HELP ME!! triangle ADB, point C lies on segment AB and forms segment CD, angle ACD measures 90 degrees. Point A is labeled jungle gym and point B is labeled monkey bars. Beth is planning a playground and has decided to place the swings in such a way that they are the same distance from the jungle gym and the monkey bars. If Beth places the swings at point D, how could she prove that point D is equidistant from the jungle gym and monkey bars? If segment DC bisects segment AB, then point D is equidistant from points A and B because a point on a perpendicular bisector is equidistant from the endpoints of the segment it intersects. If segment DC bisects segment AB, then point D is equidistant from points A and B because congruent parts of congruent triangles are congruent. If segment AD bisects segment AB, then point D is equidistant from points A and B because a point on a perpendicular bisector is equidistant from the endpoints of the segment it intersects. If segment AD bisects segment AB, then point D is equidistant from points A and B because congruent parts of congruent triangles are congruent.
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Me d is also an option but i couldn't get it in the picture
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triangle ADB, point C lies on segment AB and forms segment CD, angle ACD measure...
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