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Mathematics, 27.10.2020 20:00 jrstrom9090

Jaylin created the following expression: 2/5x βˆ’3/10 βˆ’ x + 1 7/10x βˆ’ 1/10
Jaylin created an equivalent expression using the following steps:

4/10x + (βˆ’1x) +1 7/10x + (βˆ’3/10) +(βˆ’1/10) 1 1/10x +βˆ’2/5
Is his final expression equivalent to the initial expression? Show how you know. If the two expressions are not equivalent, find Jaylin's mistake and correct it.

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Jaylin created the following expression: 2/5x βˆ’3/10 βˆ’ x + 1 7/10x βˆ’ 1/10
Jaylin created an eq...
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