The formula for the area of a trapezoid is A=\frac{1}{2}h(b_1+b_2),A= 2 1 h(b 1 +b 2 ), where hh is the height and b_1b 1 and b_2b 2 are the two bases. Rewrite the formula to solve for hh in terms of A, A, b_1b 1 and b_2.B 2 .

Question

The formula for the area of a trapezoid is A= 1/2h(b1 + b2),

where h is the height and b1 and b2 are the two bases. Rewrite the formula to solve for h in terms of A, b1 and b2

h = 2A/b1 + b2

Step-by-step explanation:

Area of a Trapezoid

= 1/2h(b1 + b2)

Rewriting the formula to solve for h, this means making h the subject of the formula

A = 1/2h(b1 + b2)

Cross Multiply

2A = h(b1 + b2)

Divide both sides by b1 + b2

h(b1 + b2)/b1 + b2 = 2A/b1 + b2

Therefore,

h = 2A/b1 + b2

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]