What is the probability that six consecutive integers will be chosen as the winning numbers in a lottery where each number chosen is an integer between 1 and 40 (inclusive)?

0.00000911843

Step-by-step explanation:

Since the number chosen is an integer between 1 and 40 (inclusive), it means that the number of terms is 40.

Thus; n = 40

Probability that 6 integers (r = 6) which is number of possible outcomes will be gotten without repetition is gotten by the combination formula which is;

C(n, r) = n!/(r!(n - r)!)

C(40, 6) = 40!/(6!(40 - 6)!)

C(40,6) = 3838380

Now, to select 6 consecutive integers, it can be done in different combinations such as;

(1 - 6, 2 - 7, 8 - 13,...e.t.c)

Total number of favorable outcomes will be 35.

Now,probability that six consecutive integers will be chosen as the winning numbers is;

P(that six consecutive integers will be chosen as the winning numbers) = number of favorable outcomes/number of possible outcomes = 35/3838380 = 0.00000911843

v: l•w•h÷2.

v: 20•6•8 ÷2

v: 960÷2

v: 480

inequality:

620-37.4p ≥ 450

the minimum amount of packages needed to be removed from the elevator is 5.

step-by-step explanation: