A rectangular field is eleven times as long as it is wide. If the perimeter of the field is 2400 feet, what are the dimensions of the field? A) Write an equation you can use to answer the given question. Let
w be the width of the field.

l=?
w=?

Step-by-step explanation:

let x=width of the field

11x=length of the field

twice the width+twice the length = perimeter

2x+22x=2400

24x=2400

x=100

11x=1100

width of the field=100 ft

length of the field=1100 ft

80° is the measure of gh

step-by-step explanation:

circle f is congruent to circle j

we have two circle with center f and j.

both circles are congruent. the radius of the circle would be equal.

see the attachment for the circle.

we are given ∠efd ≅ ∠gjh

therefore, arc (ed) = arc (gh)     (∴ circle f is congruent to circle j)

but ∠dfe=80°=arc (ed)

therefore, arc (gh) = 80°

thus, 80° is the measure of gh