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Mathematics, 27.10.2020 09:40 garzamatt7

In the process of solving 2x3 + 7x2 + 9x + 10 = 0 you test 1, 2, 5, and 10 as possible zeros and determine that none of them are actual zeros. You then discover that - 5/2 is a zero. You calculate the depressed (resulting) polynomial to be 2x3 + 2x + 4. Do you need to test 1, 2, 5, and 10 again? Why or why not?


In the process of solving 2x3 + 7x2 + 9x + 10 = 0 you test 1, 2, 5, and 10 as possible zeros and de

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